The value of cot 0 - sin (90° - 0) cos(90° - 0) is​

cos(90−θ)sec(90−θ)tanθ/cosec (90−θ)sin(90−θ)cot(90−θ)+tan(90−θ)/cotθ.

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The value of cot 0 - sin (90° - 0) cos(90° - 0) is​

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Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan theta}{1+tan ^{2}theta}

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