What is the compressibility factor (Z) for 0.02 mole of a van der Waal

(d) (0.1+(1000xx(0.02)^(2))/(V^(2)))V=20xx0.02 =0.1V^(2)-0.4V+0.4=0 =V^(2)-4V+4=0 implies" "V=2L Z=(PV)/(nRT)=(0.1xx2)/(20xx0.02)=0.5

Punjabi] What is the compressibility factor (Z) for 0.02 mole of a va

DPP No. : 21 Total Marks : 40 Max. Time : 10mln Single choice Objective (..

Solved Data: Ideal gas constant R 8.314 J mol1 K1 1 (a)

Why does CH4 have a greater value of van der Waals' constant than

Two flask A and B of equal volumes maintained at temperature 300K an

atm. 6. What is the compressibility factor (Z) 0.02 mole of a van der Waals' gas pressure of lam. Assume the size of gas molecules is negligible. Given : RT = 20

its mole fraction. Solution : P=KH​⋅X⇒PCO2( g)​=KH​⋅X(CO2​)​⇒0.01=35​×100..

A gaseous mixture contains three gaseous A,B and C with a total number

Ratio of the rate of effusion of oxygen gas 1.5 atm to that of helium gas 4.5 atm will be (1) 1:62 (2) 1:12 Yon4 13 (3) 1:22 (4) 1:3 Compressibility factor under critical state of a gas is

100ml of 0.1 M k4 [ Fe (CN)6 ] . Find the molarity of K+

Van Der Waals Equation - an overview

The following table depicts van-der-Waals coefficient

58.7 Maximum mass of hydrogen is present in(1) 0.1 mol of CH1206(2) 1.5 mol of NH3(3) 22.4 L of H2S(g) at S.T.PSo(4) 0.5 g molecule of CeH